[10(x^2)]-x+2=0

Solution for [10(x^2)]-x+2=0 equation:

Simplifying
[10(x2)] + -1x + 2 = 0

Reorder the terms:
2 + -1x + [10x2] = 0

Solving
2 + -1x + [10x2] = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
0.2 + -0.1x + x2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + -0.1x + -0.2 + x2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + -0.1x + x2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + -0.1x + x2 = 0 + -0.2
-0.1x + x2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
-0.1x + x2 = -0.2

The x term is -0.1x.  Take half its coefficient (-0.05).
Square it (0.0025) and add it to both sides.

Add '0.0025' to each side of the equation.
-0.1x + 0.0025 + x2 = -0.2 + 0.0025

Reorder the terms:
0.0025 + -0.1x + x2 = -0.2 + 0.0025

Combine like terms: -0.2 + 0.0025 = -0.1975
0.0025 + -0.1x + x2 = -0.1975

Factor a perfect square on the left side:
([x] + -0.05)([x] + -0.05) = -0.1975

Can't calculate square root of the right side.

The solution to this equation could not be determined.